V being velocity, a acceleration and t time of course.
I always thought dimensional analysis was used for figuring out things like the amount of seconds in a year. Like conversions and shit.
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XMariex
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i always thought this stuff was confusing!
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RebeccaEmOkiss
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I'm bad at that.
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EventerChick
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Oh, we did that like the first week of school in physics this year. Wish I could be of help, but it's not clicking atm.
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Siress
Quality Control Engineer
good god man...
V is m/s, a is m/s^2, t is s.
m/s = m/s + (m/s^2)*(s)^2 m/s = m/s + m Thus, not possible.
If you recall projectile motion, from Phys. or Calc., you know that the rate of change of displacement (velocity) is the integral of acceleration with respect to time. Thus, given some acceleration constant, V = a*t + Vi
Integrate that to get displacement: X = 1/2*a*t^2 + Vi*t + Xi
6:07 pm on Oct. 13, 2008 | Joined Sep. 2007 | 28 Days Active Join to learn more about SiressGeorgia, United States | StraightMale | 572 Posts | 914 Points
m/s = m/s + (m/s^2)*(s)^2 m/s = m/s + m Thus, not possible.
If you recall projectile motion, from Phys. or Calc., you know that the rate of change of displacement (velocity) is the integral of acceleration with respect to time. Thus, given some acceleration constant, V = a*t + Vi
Integrate that to get displacement: X = 1/2*a*t^2 + Vi*t + Xi
You made my whole worksheet very easy.
I wasn't thinking about converting velocity and acceleration into their basic components.
EDIT: I knew the equation itself was wrong, but I needed to be able to prove it using dimensional analysis.
Post edited at 6:14 pm on Oct. 13, 2008 by Acid World
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Siress
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No problem. Feel free to relieve yourself of some of those points in my general direction.
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